The Falling Slinky and Einstein’s Elevator

I have not known that this toy has a name at all. The ‘spring’ that can walk down the stairs is called Slinky!

We all know how the Slinky walks – but how does it fall?

This video might come as a surprise!

The authoritative article on The Falling Slinky is this one: Modelling a Falling Slinky – replacing it with a chain of masses connected by massless springs and calculating the trajectories of bottom, top and center of mass.

Edit: On replying to a comment, I searched for some written explanation by the professor featured in the video: And I found this great scientific paper an arxiv! The wave-like travelling of the “information that tension has collapsed” (as explained in the video) is put into equations.

I believe you could also explain it in the following way:

(1) If you are falling down you feel weightless – gravity is equivalent to acceleration.

You have for sure seen images of cartoon Einstein (the creator of General Relativity) in an elevator falling down in empty space (You find those images close to those cartoon spaceships emitting pulses of light from their cone ends)

(2) So the Slinky is not subject to gravity when it falls but the elastic force will contract it in the same way a Slinky stretched along a table would do.

Now we have to decide on the absolute position of the top or bottom of the Slinky: If it contracts will the bottom move up to the top or the other way round? Or will bottom and top move to the center? I think here we have to resort to considering the center of mass: From the observer’s frame of reference the COM needs to fall down as a point particle with the same mass. The top starting to move will make the COM ‘fall down’ and make the Slinky contract.

(The End)

Bonus Material: ‘Making of’ This Blog Post

Actually I came to this conclusion after playing with another thought experiment that did not work out well in the end.

I imagined the connection between the individual segments of the slinky becoming weaker and weaker until the Slinky ends up as a pile of separate rings. The rationale for this was that a Slinky is quite a weak spring – but in the explanation given above some restoring force is crucial.

The rings would be connected by strings that just keep the whole thing from falling apart. The strings would not be elastic. Thus there is hardly any elastic force, they wouldn’t be any oscillations when the bottom of the ‘string Slinky’ has been released.

Now all the rings except the top ring are suspended – each ring connected to its superior.  When the top ring is released it starts to fall – there would be no restoring force. I expect this thing to fall without any change in shape – in contrast to the Slinky – if the experiment is done in vacuum and everything is balanced carefully. In real live it would rather twist and tumble.

Probably I should test that at Christmas time –  connecting ring-shaped cookies with silvery or golden yearn would be both decorative and very close to my mental model.

19 Comments Add yours

  1. Matthew Rave says:

    “Slinky” is a word that is etched into the consciousness of any kid who grew up in the USA in the 1970’s, mostly because of the following song: http://www.youtube.com/watch?v=CM_sMM_tvX8
    If you get an earworm from that, you’re welcome.

    1. elkement says:

      Thanks, Matthew! Michelle has posted the 1960s version below :-)
      Theoretically the name should be Slinky in any language (if I trust Wikipedia on this). However, I did not know that there is any name for it in German. But we here in Europe definitely missed this song, I cannot recall any commercials.

      1. Matthew Rave says:

        Slinky is also an actual word in English, meaning “provocative”, as in a slinky dress. According to Google translate the German word would be aufreizend, as in: Aufreizend! Spaß für ein Mädchen oder einen Jungen! which sounds a tad creepy.

        1. Matthew Rave says:

          On second though, Slinky probably comes from the verb “to slink” which is roughly translated as “zu schleichen”. So maybe the toy should be called “hinterhältig” in German.

          1. elkement says:

            I was just about to answer, thanks! I did not know (or cross-check) the adjective ‘slinky’ as expected the slinky (toy) to be related to ‘to slink’. But I am eagerly waiting for new WordPress stats and search terms related to slinky ;-)

            1. Matthew Rave says:

              By the way, your Google number is now 2. Just Google “Slinky Einstein”.

            2. elkement says:

              But aren’t both Slinky and Einstein proper nouns and thus not eligible as Google number terms? ;-) You might declare slinky to be an adjective, but Einstein…?
              BTW with German terms it is rather easy to achieve a Google number of 2 as German gives you infinite options to concatenate nouns without blanks or hyphens – equivalent to the English phrases that would include blanks.

  2. M. Hatzel says:

    This physics post wasn’t as scary as the gyroscope, so I shouldn’t have put it off for a day when I knew I had hours to ponder. :) I can give you some trivial feedback, though. http://www.youtube.com/watch?v=EZL6RGkPjws is the commercial we used to see on TV as kids (the song is very powerful, though, it’s stuck in my head).

    1. elkement says:

      Thanks, Michelle! I might attempt to write a short update, based on the conversation I had with Dave (Pairodox Farm) below – and try to compress the physics into words even more!
      This ad is really nice and so clichéd 1960s, thanks a lot :-) I liked that comment on YouTube: “The stairs in the commercial are far too compact for people.they are made specifically for slinkys..Not even the 1960s building codes would allow such steps.”

      1. M. Hatzel says:

        I started a reply to this, which turned out to be too long. I think I’ll try to form my thoughts, as they connect to the post you reblogged from Dan, and post it. I’ve found a real-world problem in my children’s educational experiences, and you’ve really hit on the dilemma I’m having, that eventually we must be able to communicate some ideas/problems/solutions in mathematics… it is not enough to have only language-based discussions. This sounds enigmatic, but I’ll try to clarify in the post. Thanks.

  3. Your theoretical experiment got me thinking about physical chemistry again. By non-elastic, I am assuming you don’t mean plastical, but with a rigidly fixed length. How does that get me to physical chemistry? Covalent bonds are pretty close to what I think you mean, Now, take benzene molecules as your rings and connect them using ethylene. Of course, you won’t exactly be able to observe your rings directly, but you (i.e. your computer) could certainly calculate their behaviour

    1. elkement says:

      It’s an interesting idea to transfer the thought experiment to the atomic level – I was thinking of macroscopic metal rings connected by yarn of perfectly fixed length.
      One the one hand you cannot assign such a fixed length to any chemical bond – any linear molecule could exhibit longitudinal oscillations (The question is what the natural frequency of the oscillation would be). But obviously – on the other hand – this structure is rigid from a macroscopic perspective: Consider any rigid body – say, a diamond (covalent bonds). It falls down without changing shape; it is obviously not squeezed in a strange way ;-)
      I guess an analysis of the waves (similar to the one done in the paper) woud yield that they travel through the body extremely quick.
      Thanks for the comment!

  4. I get this setup for the moment of release, at T=0 …. but in the moment just after T=0 isn’t there instantaneously less tension in the spring (providing upward acceleration) … and not enough to counter the downward force of gravity? For the bottom part to remain stationary the tension needs to be constant. So shouldn’t the bottom begin to accelerate downward (as tension decreases) until the other end meets it … at which point there is no more counteracting tension and the thing then falls more quickly? I guess I’m just missing something. Where have I gone wrong. On another note … I loved the Slinky when I was a kid, I recall you could setup standing waves that were pretty nice. D

    1. elkement says:

      I know – these puzzles are terribly deceptive – I am not sure if I would have predicted it correctly.
      Trying to image what each part of the slinky does I prefer the explanation given by the professor in the video: “The information about the support being lost at the top needs some time to travel down to the bottom”. If the slinky would be perfectly rigid then the information would be “available” immediately at the bottom. The decrease of tension is like a wave travelling through the slinky – so it is not an instantaneous reaction.
      I tried to search some written explanation by the professor and found … a serious scientific paper! On slinky physics! Great!! http://arxiv.org/pdf/1208.4629v1.pdf (Need to add this link to the article in a minute)

      1. I do not know why I did not receive your reply in my reader Elke! I am sorry for the tardy reply. I looked at the link. I really wish physicists would learn to express ideas using words rather than integrals and derivatives … I hate it when they say things like “The modeling of the process presented here is also relatively simple, and should accessible to undergraduate students.” Talk about a put down … it’s gonna take me some time to recover! D

        1. elkement says:

          No problem!! This is not the corporate world – I am not all expecting “timely replies”.
          You are right – phrases as “simple”, “trivial”, “obvious” etc. should be banned – I apologize on behaf of the physics community ;-)
          Re language versus math: This is true pet topic of mine. I tried to put the simplest differential equation (dealing with a spring actually) into words in this post: https://elkement.wordpress.com/2012/11/20/are-we-all-newtonians/
          I believe you can put physics in words and add clever and concise arguments that can in some sense replace equations. Richard Feynman’s physics lecture are in my opinion the best example for that. But there is a big caveat: Words are actually shortcuts to something that finally has to be expressed in math. If physicists talk about e.g. “a particle feeling a force” etc. they have an equation in mind.
          You can use language to expound the math and foster the process that lets sink math into your subconsciousness – I believe this is finally not that different from learning a language. But I think the essence of physics cannot be grasped based on verbal descriptions only. It makes me cringe if “quantum physics” in its verbal form, expressed in new age-y babble or language that can be confused with that – is used to “explain consciousness” for example. I have often observed that popular physics books by notable experts (not written with any spritual metaphysical stuff in mind) are hailed by readers inclined to esoterics.
          I give it a try:
          In the case of the slinky it is imperative to understand and imagine the slinky as a chain of individual point masses connected by springs. This is also shown in the other – much shorter – article:
          http://www.wired.com/wiredscience/2011/09/modeling-a-falling-slinky/.
          Three forces act on each of the little spheres: the elastic forces exerted by its neighbors and gravity. The tricky thing is that the forces are influenced by the movements. Solving the systems of differential equations means: Calculate the force –> calculate the movement in the first millisecond –> calculate the forces… It’s an iterative process.
          In the very first moment, when the first (top) “particle” starts to move, you know all the positions of all the particles and all their velocities – all velocities are zero except the one of the first particle. It is true that “gravity acts immediately”, but for the bottom particle it is still compensated be the upward pointing elastic force exerted by its neighbor. So the last particle will not move. If the last one does not move, nothing changes for the particle above the bottom one. The only particle affected immediately is the one below the top particle, because due to the non-zero velocity of the top one the first spring has been shortened and thus the elastic is weaker in the first spring.

        2. elkement says:

          What a wall of text – sorry! I probably will promote this a blog post in the future!

          1. Yes … a wall of text but I believe your analogy of a chain of individual point masses works for me. ‘Information’ doesn’t cross the final link to the final bit of mass until forces have been transmitted via all of the intervening links first – and that takes time. Now … having said that in clear, concise, language was easier for me than the math. I agree though that ultimately all of these ideas must be translated into equations to be of any use, in a larger sense. I’m not against math, or innumerate, I simply prefer to hear my explanations first using words – and then, perhaps, using equations. Thanks for taking the time to set me straight here. D

  5. Joseph Nebus says:

    Reblogged this on nebusresearch and commented:

    Elkement’s Theory and Practice of Trying Everything has a charming post here inspired by the imagination-capturing question of what happens to a Slinky if you simply drop it (including a slow-motion video showing just how close reality can be to a Road Runner cartoon). She also puts forth an alternate explanation for just what is seen.

    Slinkies are great physics (and mathematics) tools anyway, as they let you play for a while as you pretend to be working out how to model all kinds of wave motion problems.

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